The 1800 United States presidential election in Georgia took place between 31 October and 3 December 1800, as part of the 1800 United States presidential election. The state legislature chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
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Georgia cast four electoral votes for the Democratic-Republican candidate and incumbent Vice President Thomas Jefferson over the Federalist candidate and incumbent President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. These electors were elected by the Georgia General Assembly, the state legislature, rather than by popular vote.[1]
Results
edit| 1800 United States presidential election in Georgia[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Thomas Jefferson | – | 100.00% | 4 | |
| Federalist | John Adams (incumbent) | – | – | 0 | |
| Totals | – | 100.00% | 4 | ||
See also
editReferences
edit- ^ "1800 Presidential General Election Results". U.S. Election Atlas. Retrieved July 10, 2023.
- ^ "1800 Presidential Election". 270towin.com. Retrieved July 10, 2023.