495 (four hundred [and] ninety-five) is the natural number following 494 and preceding 496.
| ||||
---|---|---|---|---|
Cardinal | four hundred ninety-five | |||
Ordinal | 495th (four hundred ninety-fifth) | |||
Factorization | 32 × 5 × 11 | |||
Greek numeral | ΥϞΕ´ | |||
Roman numeral | CDXCV | |||
Binary | 1111011112 | |||
Ternary | 2001003 | |||
Senary | 21436 | |||
Octal | 7578 | |||
Duodecimal | 35312 | |||
Hexadecimal | 1EF16 |
Mathematics
editThe Kaprekar's routine algorithm is defined as follows for three-digit numbers:
- Take any three-digit number, other than repdigits such as 111. Leading zeros are allowed.
- Arrange the digits in descending and then in ascending order to get two three-digit numbers, adding leading zeros if necessary.
- Subtract the smaller number from the bigger number.
- Go back to step 2 and repeat.
Repeating this process will always reach 495 in a few steps. Once 495 is reached, the process stops because 954 – 459 = 495.
The number 6174 has the same property for the four-digit numbers, albeit has a much greater percentage of workable numbers.[1]
See also
edit- Collatz conjecture — sequence of unarranged-digit numbers always ends with the number 1.
References
edit- ^ Hanover 2017, p. 14, Operations.
- Eldridge, Klaus E.; Sagong, Seok (February 1988). "The Determination of Kaprekar Convergence and Loop Convergence of All Three-Digit Numbers". The American Mathematical Monthly. 95 (2). The American Mathematical Monthly, Vol. 95, No. 2: 105–112. doi:10.2307/2323062. JSTOR 2323062.